Tuesday, September 25, 2012

P6 numbers, "chairs" (fr Chong yang)


My solution:

* I shall call the visible "un-overlapped" part of a chair's leg a "leg stub" for ease of reference.

Note that when measured from floor to foot of 4th chair, we are measuring 3 leg stubs (1 fewer than the total no. of chairs stacked up)

3 leg stubs --> 37.2cm
1 leg stub --> 37.2cm / 3 = 12.4cm

With 10 chairs stacked in this manner, there are only 9 leg stubs (10-1=9)

9 leg stubs --> 12.4cm x 9 = 111.6cm   
(or  just 37.2 x 3 = 111.6)

Therefore, the height of each chair is:
206.9 - 111.6 = 95.3 (cm)

Option: (2)