Hope that no one solves this question (b) in the way shown above!
My solution:
2011/8 = 251R3
(a) Since the remainder is 3, the last number in this series is 3
The number of terms in this series is 251+1 = 252 ( The "+1" is to cater to the last tern "3")
(b) The sum of the series
= 252/2 x (2011 + 3)
= 126 x 2014
= 253 764
