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Hope that no one solves this question (b) in the way shown above! 

My solution:

 2011/8 = 251R3 

(a) Since the remainder is 3, the last number in this series is 3

The number of terms in this series is 251+1 = 252  ( The "+1" is to cater to the last tern "3")

(b)   The sum of the series 

= 252/2  x (2011 + 3)

=  126 x 2014

=    253 764

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