P5 Area and Perimeter (Fr Nanyang Primary)

P5 whole numbers (fr Rosyth sch)

P5 Fractions and Ratio (Fr: rosyth Sch)

P5 fractions (fr Priscilla )

P5 angles (fr Priscilla )

P5 fraction (fr mind stretcher)

I would recommend that the "320" be changed to "315".

Then answer for number of Caleb's sticker would be 675.

P5 rates (Mind stretcher)

My ans is $24.50

P5 Triangles and Ratio (Taken from P5 CMPFAL by Marshall Cavendish)2

P5 Triangles and Ratio (Taken from P5 CMPFAL by Marshall Cavendish)1

P5 Triangles (From NMOS 2010 Preliminary Round )4

P5 Triangles (From NMOS 2010 Preliminary Round )3

P5 Triangles (From NMOS 2010 Preliminary Round )2

P5 Triangles (From NMOS 2010 Preliminary Round )

P5 triangles

Find the areas of X and Y.

P6 percentage (fr shoe)

P6 whole numbers (Fr Nanyang CA1, Fr shoe)

P6 fraction and percentage (fr shoe)

http://www.showme.com/sh/?h=j3nCbWS

P6 ratio (fr shoe)

P6 pattern (fr shoe)

P4, P5, P6 whole numbers ( counting )

(a) How many squares are there?
(b) How many rectangles are there?

Sec4 A-Math: Trigo (Fr Lu Shi)

P5 fractions (from mind stretcher)

P5 fractions (fr: hanyin)

A box contains 20-cent coins n 50-cent coins.1/4 of the number of 20-cent coins is equal to 3/5 of the number of 50-cents coins.there is a total of 102 coins in the box.find the total value me all the coins in the box.
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My solution

http://www.showme.com/sh/?h=MsH2Crw
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Sec 1: whole numbers: Composite numbers

My Solution:

Part (c)

Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18 and 36

Factors of 54: 1, 2, 3, 6, 9, 18, 27 and 54

Since 1, 2, 3 are prime numbers, the composite numbers which are factors of both 36 and 54 are only:

6, 9 and 18

Part (d)

LCM of 24 and 36 is 72.   (Hope you know how to get this ;p )

The smallest number that we are looking for that when divided by either 24 or 36 and yield a remainder of 11 would be:  

72 + 11 = 83

Sec 1: whole numbers LCM, HCF

My solution:

Given that one of the number is 56.

With the LCM being 504,

      504 / 56 = 9

The other number must be a multiple of 9.

With the HCF of the 2 original numbers being 8,

The smallest possible value of the 2nd number has to be 8x9 = 72